A 2.20 x 10-6 F capacitor is hooked up to a 14.0 V power supply. How
much energy is stored in the
capacitor?

Step-by-step explanation:

Given that,

The capacitance of the capacitor,

Voltage of the power supply, V = 14 V

We need to find the energy stored in the capacitor.

The formula for the stored energy in the capacitor is given by :

Put all the values,

So, of energy is stored in the capacitor.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

won't that be plagrisim thought?

step-by-step explanation: