A sphere with the diameter of 10 cm is being painted. how much more paint is now needed to paint the sphere that has 4 times the OG diameter. 4
8
16
64

The total surface area of the solid =Total surface area of the cube+Curved surface area of the hemisphere−Area of the base of the hemisphere.

=6a

2

+2πr

2

−πr

2

=[6×10

2

+2×3.14×5

2

−3.14×5

2

]cm

2

=600+157−78.5=678.5cm

2

Cost of painting=Rs.5 per 100cm

2

∴,Cost of painting the solid=678.5×

100

5

=Rs.33.90

Hence, the approximate cost of painting the solid so formed is Rs.33.90

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step-by-step explanation:

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: