Write 11 k-6 (2k+5)in expanded form and find the sum

Option B

Step-by-step explanation:

Expression representing the series is,

Here, k = Number of terms

By placing k = 6, 7, 8, 9, 10, 11 in the expression we can get the terms of the series.

For k = 6,

(2k + 5) = 2(6) + 5

            = 17

For k = 7,

(2k + 5) = 2(7) + 5

             = 19

For k = 8,

(2k + 5) = 2(8) + 5

            = 21

For k = 9,

(2k + 5) = 2(9) + 5

            = 23

For k = 10,

0(2k + 5) = 2(10) + 5

            = 25

For k = 11,

(2k + 5) = 2(11) + 5

            = 27

Therefore, expanded form will be,

17, 19, 21, 23, 25, 27

There, is a common difference in each successive to previous term,

d = 19 - 17

d = 2

Number of terms 'n' = 6

First term = 17

Sum of an arithmetic sequence is given by,

Therefore, sum of the given sequence will be,

   = 3(34 + 10)

S = 132

Option B will be the correct option.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.