The volume of a sample of oxygen is 200.0 mL when the pressure is 3.00 atm and the temperature is 310 K. What is the new temperature if the
volume increases to 400.0 mL and the pressure decreases to 2.00 atm?*
322.3K
482.8 K
O 413.3K
686.0 K

9514 1404 393

  C  413.3K

Step-by-step explanation:

Temperature is proportional to volume and pressure. Pressure has decreased by a factor of 2/3, and volume has increased by a factor of 400/200 = 2. So, the new temperature is ...

  (310 K)(2/3)(2) = 413 1/3 K ≈ 413.3 K

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%