a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance it covers? i'll give brainliest to whoever answers first/correctly!

we know that

1 ft> is equals to 12 in

the ramp is 12 inches tall> 1 ft tall

A ramp measures>  6 ft long

applying the Pythagorean theorem

c²=a²+b²

where

c> 6 ft long

a> horizontal distance

b> 1 ft tall

a²=c²-b²> a²=6²-1²> a²=35> a=√35> a=5.92 ft

the answer is

5.92 ft

6.08 or so

Step-by-step explanation:

The height is 1 foot, while the length is 6 feet.

You can use the Pythagorean Theorum to solve this, as you plug in the values.

The theorum states that A squared plus B squared = C squared, where A is  the length, and B is the width. (It doesn't matter if A is the width and B is the length either.)

So if we plug in the values:

1 squared plus 6 squared = C squared.

1 + 36 = 37

Since it is C squared, we can find the square root of 37, which is something like 6.0827625302982196889996842452021.

So usually we round to the hundredths place, so we can use 6.08.