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Mathematics, 24.05.2021 21:20 lechinastarks317

H(-3), h(5), h(2), h(0)

h(x) = {x + 1, x < 2
{2x - 1, x > 2


H(-3), h(5), h(2), h(0)
h(x) = {x + 1, x < 2
{2x - 1, x > 2

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Answers: 2

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H(-3), h(5), h(2), h(0)

h(x) = {x + 1, x < 2
{2x - 1, x > 2
...
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