The relationship between the distance biked and time for Jeremy can be represented by the equation y = 12x, where he biked y miles in x hours. Below is a table that represents the number of hours and miles Kevin rides. Time in hours (X) Distance in miles (y)
1.5 8.25
2 22
3.5 19.25
4 33

A third biker, Lauren rides twice as fast as Kevin. Use Y to represent the number of miles Lauren travels in x hours. Assume all bikes ride at a constant rate.

Which Statement accurately compares the biking speed of Lauren to Kevin and Jeremy?

a) The biking speed of Lauren is greater than the biking speeds of both Kevin and Jeremy.
b) The biking speed of Lauren is less than the biking speeds of both Kevin and Jeremy.
c) The biking speed of Lauren is greater than the biking speed of Kevin and less than the biking speed of Jeremy.
d) The biking speed of Lauren is less than the biking speed of Kevin and greater than the biking speed of Jeremy.

I put c I have the same question I'm doing a test

Step-by-step explanation:

answer=c

Step-by-step explanation:

is the right answer

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.