Find the coordinates of the circumcenter of Triangle ABC with vertices A (1, 4), B (1, 2), and C (6, 2). A. (5, 2)

B. (3, 4)

C. (2.5, 1)

D. (3.5, 3)

y=mx+

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)