Plzzz help A bag of marbles has 10 red marbles, 4 green marbles, and 6 blue marbles. A marble is randomly drawn from the bag before another marble is drawn, without replacement. What is the probability that a green marble and then a red marble are selected? Enter your answer as a fraction in simplest form in the box

Step-by-step explanation:

A bag contains 8 red marbles, 3 blue marbles and 7 green marbles.

Total = 18 marbles.

Probability of drawing three red marbles = probability of drawing one red without replacement + probab of drawing another without reeplacement + probab of drawing a third without replacement.

Probability of drawing three red marbles = 8/18 + 7/17 + 6/16 = 0.4444 + 0.4118 + 0.3750 = 1.2312.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

false

step-by-step explanation: