the height h in feet of an object shot straight up with initial velocity v in feet per second is given by h=16t^2 + vt + c where c is the initial height of the object above ground a model rocket is shot vertically up from a height of 6 feet above sea he ground with an initial velocity of 22 feet per second. will it reach a height of 10 feet?

i can

step-by-step explanation:

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

it is not that hard all u have to do is plot the graph

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm