Identify the initial conditions y(0) and y'(0) for the vertical motion of an object, if the object is thrown downward at a velocity of 6 m/s from a height of 30m. (take the origin to be on the ground)

The right solution is "y(0) = 30 m" and "y'(0) = -6 m/s²".

Step-by-step explanation:

Given,

Velocity,

u = -6 m/s

Height,

h = 30 m

Now,

By using shifting of origin, we get

⇒  

hence,

The value of y(0) is:

y(0) =

      =

The value of y'(0) is:

y'(t) =

y'(0) =