A number is greater than 8. The same number is less than 10. The inequalities x > 8 and x < 10 represent the situation Which best explains the number of possible solutions to the inequality?
There is one solution because 9 is the only number between 8 and 10.
O There are a three solutions because 8, 9, and 10 are possible solutions.
O There are a few solutions because there are some fractions and decimals between 8 and 10.
There are infinite solutions because there is always another number between any two numbers.

Option 4

Step-by-step explanation:

Let any two real number a and b (no matter +ve, -ve or 0). a ≥ b

The average of them will always lie in between them or be equal(if 0).

Let's prove : According to the statement,

a ≥ (a + b)/2 ≥ b

2a ≥ a + b ≥ 2b

2a ≥ a + b and a + b ≥ 2b

a ≥ b and a ≥ b, as we assumed.

Moreover, as the average exists in between a and b, we have the average (a + b)/2. Similarly, there exists one more average of (a + b)/2 and a or b, which definitely lie between a and b as (a + b)/2 lies there and smaller than a and b.

In the same order, we can have many average and the process would stop. This leads to infinite number between a and b.

Notice that we talked about all the numbers moreover there are many irrational(non-terminating like 9.898989 etc numbers as well.

Option (4), infinite solutions.

Note: we solved for all the number (not specifically odd, even, natural, whole, integer, etc).

x=0

step-by-step explanation:

idk u tell me

step-by-step explanation: