Solve for a: 3a + 11 > 5 Which graph shows the solutions?
Hot+
-5 -4 -3 -2 -1 0 1 2 3 4 5
AH
-5-4-3-2-1 0 1 2 3 4 5
A+++
HHH
-5-4-3-2-1 1 2 3 4 5
A+ HOHHH
-5-4-3-2-1 0 1 2 3 4 5

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract

mgxmgzmgzzzlgxhhhx. dlulhx

four boxes of pizza

hope this