If an arrow is shot upward on the moon with a velocity of 50 m/s, its height (in meters) after t seconds is given by H = 50t − 0.83t^2.

The velocity is: 48.34m/s

Step-by-step explanation:

Given

--- initial velocity

Required

The velocity after 1 second

We have:

and

Differentiate

We have that:

So, the equation becomes

Substitute 1 for t

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step-by-step explanation:

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