Please help with this using the chain rule

a is the answer

Step-by-step explanation:

y = ( x^2 +2x+ 5 )^6,

let u be equal to x^2 + 2x + 5

y = u^6 '

dy|du = 6u^5, du|dx = 2x + 2

dy|dx = dy|du × du|dx = 6u^5 ×( 2x + 2 )

= 2( x + 1) × 6u^5 = 12 ( x + 1 )( x^2 + 2x +5)^5

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.