Find the surface area of the regular pyramids. Round your answer to the nearest tenth.

S.A = 147.35 cm²

Step-by-step explanation:

Surface area of the triangular pyramid = base area + ½(perimeter of base*slant height)

Base area = ½*bh

b = 7 cm

h = 6.1 cm

Base area = ½*7*6.1 = 21.35 cm²

Perimeter of triangular base = 7 + 7 + 7 = 21 cm

slant height = 12 cm

Plug in the values into the equation

S.A = 21.35 + ½(21*12)

S.A = 21.35 + 126

S.A = 147.35 cm²

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)