The overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8 cm. A) find the probability that an individual distance is greater than 218.90 cm
B) find the probability that the mean for 15 randomly selected distances is greater than 204.20 cm
C) why can the normal distribution be used in part B, even though the sample size does not exceed 30

4

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;