Help me with this math question please I'm giving away brainliests ​

Step-by-step explanation:

Given function is,

This function is not defined at "x(x - 2) = 0"

Therefore, for the values of x = 0 and 2, given function is not defined.

Vertical asymptote → x = 2 [Denominator = 0]

For Horizontal asymptote →

Therefore, horizontal asymptote → y =

x-intercept,

For f(x) = 0,

Numerator of the function = 0

2x² + 6x = 0

2x(x + 3) = 0

x = -3

Therefore, x - intercept → (-3, 0)

For y-intercept,

x = 0

f(0) = 0

Therefore, graph has no y-intercept.

For holes on the graph,

Since, function is not defined at x = 0,

f(x) =

f(0) =

     =

Therefore, hole on the graph →

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step-by-step explanation: