Solve by substitution

2x -9y = 14

x = -6y + 7

first replace the x of the first equation with the -6y + 7

which turns out

2 ( -6y + 7 ) -9y = 14

by following brackets first rule we can do

- 12y + 14 -9y = 14

we can arrange the following to

- 12y - 9y + 14 = 14

so like terms are together

we shifting 14 over

- 12y - 9y = 14 - 14

- 21y = 0

meaning y = 0

then we can replace x = -6y + 7 with

x = -6 (0) + 7

by multiplying with brackets first rule we come to

x = 0 + 7

x = 7

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3