Describe fully the single transformation that takes shape p onto shape q

The single transformation that takes shape 'p' onto shape 'q' is a dilation by a scale factor of 3 with the center point (1, 0)

Step-by-step explanation:

The coordinates of the vertices of shape ΔP are;

A(2, 3), B(2, 1), C(3, 1)

The length AB = 3 - 1 = 2

The length CB = 3 - 2 = 1

∴ The length AC = √(2² + 1²) = √5

The coordinates of the vertices of shape ΔQ are;

A'(4, 9), B'(4, 3), C'(7, 3)

The length A'B' = 9 - 3 = 6

The length C'B' = 7 - 3 = 3

∴ The length A'C' = √(6² + 3²) = √(45) = 3·√5

∴ Figure Q ΔA'B'C' is a dilation of figure P ΔABC by a scale factor of A'B'/AB = 6/2 = 3

The distance of point B(2, 1) from the point (1, 0) = √((2 - 1)² + 1²) = √2

The distance of point B'(4, 3) from the point (1, 0) = √((4 - 1)² + 3²) = 3·√2

Therefore, the distances of points on figure Q from (1, 0) = 3 × the distances of points on figure from (1, 0)

Therefore, figure 'Q' can be obtained from figure 'P' by a dilation of figure 'P' by a scale factor of 3 with the center of dilation at point (1, 0).

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2