Solve the following initial value problem and determine the interval of validity dx/dt = 6x2t, x(1) = 1 /25 . What if the initial condition is now x(-4) = - 1/20 ?

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =

many reason,

step-by-step explanation:

if im not mistaking its

step-by-step explanation:  

slope intercept form is y = mx + b