Please do this <33333

We know that,

In a right-angled triangle,

Hypotenuse ² = Base ² + Height ²

1 – 10 ² = 6 ² + X ²

Or, X ² = 10 ² – 6 ²

Or, X ² = 100 – 36

Or, X ² = 64

Or, X = √ 64

Or, X = 8 Units

2– X² = 7² + 3²

Or, X² = 49 + 9

Or, X² = 58

Or, X = √58

Or, X = 7.61 Units ( Approx )

3 – 15 ² = EF ² + 9

Or, EF² = 15 ² – 9 ²

Or, EF ² = 225 – 91

Or, EF ² = 134

Or, EF = √ 134

Or, EF = 11.6 Inches ( Approx)

.II} 1 – Here the length of the ladder will be the hypotenuse.

Hence, Hypotenuse = 13 Metre

.Now, The vertical wall will be the height.

Hence, Height = 12 Metre

Distance of the foot of the ladder to the wall will be the base.

Let base be B.

Now, Hypotenuse ² = Base ² + Height ²

Or, 13² = B² + 12²

Or, B² = 13² – 12²

Or, B² = 169 – 144

Or, B² = 25

Or, B = √25

Or, B = 5 Metre

Hence, the distance of the foot of the ladder from the wall is 5 metre apart.

the perimeter is increased by a factor of 2

(3x-8) or (3x+8)

step-by-step explanation: