Hi, I need help on this one! Perform the indicated operation.
a^2 - 2a+1/6 divided by (a^2-1)=

The denominator of the resulting fraction is

→ 6(a - 1)
→6(a + 1)
→6

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.