(4pq+3q)² - (4pq - 3q)²​

48pq².

Step-by-step explanation:

(4pq+3q)² - (4pq - 3q)²​

This is the difference of 2 squares so we can use the identity

a^2 - b^2 = (a - b)(a + b):

(4pq+3q)² - (4pq - 3q)²​

= (4pq + 3q - (4pq - 3q)(4pq + 3q + (4pq - 3q)

= (4pq + 3q - 4pq + 3q)(4pq + 3q + 4pq - 3q)

= 6q * 8pq

= 48pq².

48pq²

Step-by-step explanation:

As we know,

(a + b)² = a² + 2ab + b²

and

(a – b)² = a² – 2ab + b²

So,

(4pq+3q)² - (4pq - 3q)²​

= [(4pq)² + 2 X 4pq² X 3q + (3q)²] – [(4pq)² -  2 X 4pq² X 3q + (3q)²]

= (16p²q² + 24pq²+ 9q²) – (16p²q² – 24pq²+ 9q²)

= 16p²q²+ 24pq²+ 9q² – 16p²q²+ 24pq² – 9q²

= 24pq² + 24pq²

= 48pq²

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2