Find the measure of the indicated angle.

pls help !!

5. m<A = 25.3°; m<B = 64.7°

6. m<A = 40.2°; m<B = 49.8°

Step-by-step explanation:

Recall: SOHCAHTOA

5. Reference angle = <A

Opposite = 9

Adjacent = 19

Apply TOA:

Tan A = Opp/Adj

Tan A = 9/19

A = Tan^{-1}(9/19)

A = 25.3461759° ≈ 25.3° (nearest tenth)

Reference angle = <B

Opposite = 19

Adjacent = 9

Apply TOA:

Tan B = Opp/Adj

Tan B = 19/9

B = Tan^{-1}(19/9)

B = 64.6538241° ≈ 64.7° (nearest tenth)

6. Reference angle = A

Opposite = 20

Hypotenuse = 31

Apply SOH:

Sin A = Opp/Hyp

Sin A = 20/31

A = sin^{-1}(20/31)

A = 40.2° (nearest tenth)

Reference angle = B

Adjacent = 20

Hypotenuse = 31

Apply CAH:

Cos B = Adj/Hyp

Cos B = 20/31

B = cos^{-1}(20/31)

B = 49.8° (nearest tenth)

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female

answer: yes, since the line has a steeper rate of change than the exponential the y-values will be greater and they will only intersect one time.