2x^2-50=0
Just use and algebraic method

x = 5, x = -5

Step-by-step explanation:

First, you can notice both terms of the equation are divisible by 2, so you can factor it out to get:

2(x^2 - 25) = 0

You can recognize the expression x^2 - 25 as the special product for the difference of squares, so it would be factored into (x + 5)(x - 5). When we plug it in we get:

2(x + 5)(x - 5) = 0

Now, we can use the zero-product property to get two equations:

x + 5 = 0

-and-

x - 5 = 0

Solving them both we get:

x = 5, x = -5

i think it is c, not positive though

step-by-step explanation: