The graph of which function has an amplitude of 3 and a right phase shift of ? y = 3+ sin 2(x - 5)
y = 3sin 2(2
y = 3+ sin 2 (2+)
y = 3sin 2(x + 5)

Option 4

Step-by-step explanation:

Equation representing the sine function is,

y = Asin[B(x- C)] + D

Here, A = Amplitude

B =

C = Phase shift

D = Vertical shift

If the amplitude of the the given function = 3 and right phase shift =

Therefore, equation of the sine function will be,

By comparing this equation with the given options,

Equation representing right phase shift = and amplitude = 3,

This equation represents right phase shift = and amplitude = 3.

Therefore, Option 4 is the correct option.

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step-by-step explanation:

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