A jar contains 6 blue gumballs, 4 yellow gumballs, and 8 red gumballs. What is the probability of choosing a yellow gumball and then a red gumball if the first gumball is placed back into the jar before the second is chosen?

2/9 or 22.22% and 4/9 or 44.44%

Step-by-step explanation:

6+4+8=18   4/18=2/9   8/18=4/9

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

if x decreases by 4 then y increases by 10

step-by-step explanation: