Find the area and perimeter of the figure below

p ≈ 97 cm

a = 390 cm²

Step-by-step explanation:

First figure out the missing lengths

The triangle on the right is a standard 9 - 12 - 15 right triangle

The triangle in the left is a right isosceles triangle so the sides are both the same 12cm.  The hypotenuse is found using c² = a² + b² and is approx 17 cm

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perimeter

p ≈ 12 + 22 + 9 + 15 + 22 + 17

p ≈ 97 cm

Area

a = left triangle + rectangle + right triangle

a = (1/2)(12*12)  + (12*22) + (1/2)(9*12)

a = 390 cm²

divide by 5

step-by-step explanation:

60/5 = 12