I will mark you brainlist! Alison will roll a number cube and flip a coin for a probability experiment. The faces of the number cube are labeled 1 through 6. The coin can land on heads or tails. If Alison rolls the number cube once and flips the coin once, which of the following lists the only outcomes when the number cube lands on a number greater than 3?

A. 3, Heads
3, Tails
4, Heads
4, Tails
5, Heads
5, Tails
6, Heads
6, Tails
B. 4, Heads
4, Tails
5, Heads
5, Tails
6, Heads
6, Tails
C. 4, Heads
5, Tails
6, Heads
D. 1, Heads
1, Tails
2, Heads
2, Heads
3, Heads
3, Tails
4, Heads
4, Tails
5, Heads
5, Tails
6, Heads
6, Tails

B. 4, Heads

4, Tails

5, Heads

5, Tails

6, Heads

6, Tails

Step-by-step explanation:

Given that the cube is labelled 1 to 6 and the coin has a head or a tail, the only outcome when the number cube lands on a number greater than 3 means that the cube lands on 4 or 5 or 6.

On the other hand, the coin may give a head or a tail.

In light of this, the possible answers are;

4, Heads

4, Tails

5, Heads

5, Tails

6, Heads

6, Tails

Hence option B is right

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen