WILL GIVE BRAINLIEST Q1) The coordinates of 3 the vertices of a parallelogram ABCD are A (-4,3), B (5,-5), and C (15,-1).
a) Find the coordinates of the point of intersection of the diagonals.
b) Find the coordinates of the point D.
c) Find the area of parallelogram ABCD.?

Let coordinates of vertex D be (x,y)

In parallelogram diagonals are bisect each other.

∴ Mid-point of AC= Mid-point of BD

⇒ (

2

3+(−6)

,

2

−4+2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,

2

−2

)=(

2

−1+x

,

2

−3+y

)

⇒ (

2

−3

,−1)=(

2

−1+x

,

2

−3+y

)

Now,

⇒

2

−3

=

2

−1+x

⇒ −6=−2+2x

⇒ −4=2x

∴ x=−2

⇒ −1=

2

−3+y

⇒ −2=−3+y

⇒ 1=y

∴ y=1

∴ Coordinates of vertex D is (−2,1)

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

you forgot an image

step-by-step explanation: