Half of a class took Form A of a test, and half took Form B. Of the students who took form B, 39% passed. What is the probability that a randomly chosen student took Form B and did not pass?

0.305 = 30.5% probability that a randomly chosen student took Form B and did not pass

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Took Form B.

Event B: Did not pass.

Half of a class took Form A of a test, and half took Form B.

This means that

Of the students who took form B, 39% passed.

So 100 - 39 = 61% did not pass, which means that .

What is the probability that a randomly chosen student took Form B and did not pass?

0.305 = 30.5% probability that a randomly chosen student took Form B and did not pass

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.