Which function's graph has x-intercepts at x=−1 and x=3, and a vertex at point (1,−4)?

I  not know this problem at all.

Step-by-step explanation:

Top right option: g(x) = (x-1)(x+3)

Step-by-step explanation:

x=-1 is the solution to x+1=0

x=3 is the solution to x-3=0

Therefore, your expression so far is (x+1)(x-3) or x²-2x-3.

Since the vertex must be (1,-4) we must check if x=1 satisfies the equation x=-b/2a:

x=-b/2a

1=-(-2)/2(1)

1=2/2

1=1

Both sides are equal to each other, so the final function is g(x) = (x-1)(x+3)

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

i think the answer is b.

step-by-step explanation:

not 100% sure though.