What is the greatest common factor of 35b^2, 15b^3, and 5b?

The first expression can be rewritten as

35 {b}^{2} = 5 \times 7 \times {b}^{2}35b

2

=5×7×b

2

The second expression is rewritten as

15 {b}^{3} = 3 \times 5 {b}^{3}15b

3

=3×5b

3

The third expression is

5b = 5 \times b5b=5×b

The greatest common factor is the product of the least powers of the common factors.

5b

Step-by-step explanation:

35b^2 = 5b(7b)

15b^3 = 5b(3b^2

5b = 5b(1)

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

p = 6s

step-by-step explanation: