What is the inverse of the function h(x)=\dfrac{3}{2}(x-11)h(x)= 2
3
​
(x−11)h, left parenthesis, x, right parenthesis, equals, start fraction, 3, divided by, 2, end fraction, left parenthesis, x, minus, 11, right parenthesis?
h^{-1}(x)=h
−1
(x)=h, start superscript, minus, 1, end superscript, left parenthesis, x, right parenthesis, equals

Step-by-step explanation:

Given :-

And we need to find the Inverse of the function . So for that firstly replace h(x) with y , we have ,

h(x) = 3/2 ( x -11)

y = 3/2 ( x - 11)

y = 3/2x - 33/2

x = 3/2y - 33/2

x + 33/2 = y × 3/2

y = (2x + 33)×2/3

y = 4x/3 + 22

h-¹(x) = 4x/3 + 22

Hence the inverse of the function is 4x/3 + 22

t= 1/3.

hope this .

step-by-step explanation:

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )