Find three consecutive integers whose average is 20. please show work!!

19,20,21

Step-by-step explanation:

The average is 20. The numbers can be written as: 20+a, 20 +b, 20+c, with a, b, c integers (positive and negative, but higher than - 19),with a+b+c =0.

You have to find the combination a, b, c with the smallest positive integer as its higher number.

Obviously, you start with 1, and find - 1,0,+1 as a suitable solution.

Therefore, the numbers are 20-1, 20,20+1

=> 19,20,21

4x times 5x equals 20x

20x times 1x equals 20x

15x plus 5x equals 20x

Step-by-step explanation:

hope it helps

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^