2 a) Solve for c: E = mc

b) Solve for m: a=f/m
c) Solve for x: -6=-6(3x – 8)
d) Solve for y: 3 - 5y| = 3
e) Solve for x: 2 - 3(2x - 1) = 17

When you have 25 numbers, and jake picks 3 random numbers and puts them back, what is the chance bob has of picking those 3 numbers when he picks 6 random numbers (without putting them back)? explain.