Ball falls so that its distance above ground can be modeled by the equation s
=
−
16
t
2
+
100
s=−16t
2
+100 , where
s
s is the distance above the ground in feet and
t
t represents time in seconds. According to this model, how many seconds does it take for the ball to hit the ground? Round to the nearest tenth if necessary.

6.25 seconds

At ground level the height of ball is 0, i.e., h=0.

Using zero product property, we get   -16t -100

= -16t + 100 + 100s

= -16(t + 6.25)  -16(ts + -6.25)

=  6.25s

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.