Factorize 2x⁴+x³-14x²-19x-6
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Step-by-step explanation:

Consider given the expression,

⇒2x4+x3−14x2−19x−6

⇒x3(2x+1)−(14x2+19x+6)

⇒x3(2x+1)−(14x2+7x+12x+6)

⇒x3(2x+1)−[7x(2x+1)+6(2x+1)]

⇒x3(2x+1)−(2x+1)(7x+6)

⇒(2x+1)(x3−7x−6)

Hence, this is the answer.

As (x+2) and (x-3) are factors of p(x), therefore g(x) = (x+2)(x-3) = x² - x - 6 is a factor of p(x). Let divide p(x) by g (x)to obtain the quotient as a quadratic in x and then factorise the quotient. So , when you divide p(x) by g(x) you will get 2x² + 3x + 1.29-Jun-2019

Step-by-step explanation:

As (x+2) and (x-3) are factors of p(x), therefore g(x) = (x+2)(x-3) = x² - x - 6 is a factor of p(x). Let divide p(x) by g (x)to obtain the quotient as a quadratic in x and then factorise the quotient. So , when you divide p(x) by g(x) you will get 2x² + 3x + 1.29-Jun-2019

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.