How do you factor y=6x^2-x-2

(2x+1)(3x-2)

Step-by-step explanation:

Given :-

We need to factor out the given expression. For that we may use the middle term splitting method. Taking the equation,

y = 6x² - x - 2

y = 6x² - 4x + 3x-2

y = 2x ( 3x -2) +1( 3x -2)

y = (2x + 1)(3x -2 )

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !