What is the equation of a line that passes through (-6,2) and has a slope of '-(1)/(2)'?

y=(-1/2)x-1

Step-by-step explanation:

With a slope of -1/2, we know that the m value in y=mx+b is -1/2

y=(-1/2)x+b

To get the b value, we substitute y and x with the coordinates given.

2=(-1/2)-6+b

2=3+b

b=-1

Now we have the b value, we put the equation back together

y=(-1/2)x-1

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option