A jar contains 2 orange, 4 green, 2 white and 2 black balls. What is the probability of drawing an orange ball without putting it back, then drawing a black ball? (write your answer as a simplified fraction)

2/45

Step-by-step explanation:

We are told that:

A jar contains 2 orange, 4 green, 2 white and 2 black balls.

The total number of balls in the jar is calculated as:

2 orange balls + 4 green balls + 2 white balls + 2 black balls = 10 balls

The probability of drawing an orange ball = P(Orange) = 2/10

The probability of drawing a black ball = P(Black) = 2/10

Therefore, the probability of drawing an orange ball without putting it back, then drawing a black ball is calculated as:

2/10 × 2/9 = 4/90

= 2/45

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: