The plane region is revolved completely about the x-axis. Find its surface area in EXACT form (in terms of pi and/or with simplified radicals as necessary). ​

The Given plane region is missing attached below is the plane region

answer : 24 π  or 75.40 sq. units

Step-by-step explanation:

Given data :

Height of plane region = 3

base of plane region  = 4

When we revolved the plane region completely we will we forming a cone hence we will calculate for the surface area of a cone

Radius of the new cone = 3

Height of the cone = 4

slant height of the cone ( l )  =  = 5

surface area of cone = πr^2 + πrl

                                   = π ( 3 )^2  + π (3 ) ( 5 )

                                   = 24 π  or 75.40 sq. units

n

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.