The class average on a math test was 80.3 and the standard deviation was 5.7. What percentage of the class scored above a 86?

= 15.866%

Step-by-step explanation:

The class average on a math test was 80.3 and the standard deviation was 5.7.

What percentage of the class scored above a 86?

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 86

μ is the population mean = 80.3

σ is the population standard deviation = 5.7

Hence:

z = 86 - 80.3/5.7

z =1

Probability value from Z-Table:

P(x<86) = 0.84134

P(x>86) = 1 - P(x<86) = 0.15866

Converting to Percentage

= 0.15866 × 100

= 15.866%

Therefore, the percentage of the class scored above a 86 is 15.866%

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

(-5,-28)

i graphed to on desmos.