A 38-foot piece of string is stretched from the top of a 13-foot flagpole to the ground. How far is the base of the flagpole from the end of the piece of string? Round your answer to the nearest hundredth

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

we are given the Hyp (38) and the Opp (13) and are being asked to find the Adj

So find the angle at the point that the string hits the ground

Sin(Ф)= 13 / 38

Ф = arcSin( 13 / 38 )

Ф = 20.00519°

now use the angle and one of the known sides to find the Adj side (length from the flag pole)

Tan(20.00519°) = 13 / Adj

Adj = 13 / Tan(20.00519°)

Adj = 35.707

dist. from flag pole to string is  35.71 feet  (rounded to nearest 100th)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

i would say b) is your answer

sorry if im wrong

step-by-step explanation: