2. Write two equations for this problem. Then, use the two equations to solve the system. Kim is selling pies for a school fundraiser. She sold 6 pecan pies and 4 chocolate pies and earned $104. The cost for a chocolate pie is one more dollar than the pecan pie. How much does each pie cost?

570, the answer is 570, hope it

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%