A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.

Probability of getting doubles = 1/4

Step-by-step explanation:

Given - A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.

To find - Using a sample space diagram, find the probability of getting a double.

Proof -

Given that,

A four-sided spinner is spin twice.

So,

The Sample Space becomes

S = { (1, 1), (1, 2), (1, 3), (1, 4)

       (2, 1), (2, 2), (2, 3), (2, 4)

       (3, 1), (3, 2), (3, 3), (3, 4)

       (4, 1), (4, 2), (4, 3), (4, 4) }

So,

n(S) = 16

Now,

Let A is the event Getting a double, So,

A = { (1, 1), (2, 2), (3, 3), (4, 4) }

and

n(A) = 4

So,

The Probability of getting doubles = n(A) ÷ n(S)

                                                         = 4 ÷ 16

                                                         = 1/4

∴ we get

Probability of getting doubles = 1/4

c is the answer

step-by-step explanation: