4x^3 -5x^2-23x+6 what is the distance to the nearest hundredth of a unit , between the two zeros that are closest to each other?

2.25

Step-by-step explanation:

Using synthetic divison (work below)

I found factored it to equal the following:

(x+2)(x-.25)(x-3)

which means that the zeroes are

(-2,0) (.25,0) (3,0)

The distance between the first and second zero are closest and their distance is 2.25

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

c

step-by-step explanation: