A line passes through the points (3,0) and (4,1). What is the y—intercept of the line?

(0,-3)

Step-by-step explanation:

Use the point slope form of a line: y = mx = b, where m is the slope and b is the y-intercept

First solve for m:

m = (Y2-Y1)/(X2-X1)

m = (1-0)/(4-3)

m = 1/1 = 1

Using the slope above, plug either point into the equation and solve for b. I used (3,0) but (4,1) would give the same result:

y = mx +b

0 = 1(3) + b

0 = 3 +b

-3 = b

SOLUTION: y-intercept is (0,-3)

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.