3. The table below shows the lengths and corresponding ideal weights of sand sharks. 60
66
68
Length
Weight
62
114
64
124
70
149
72
158
105
131
139
a) Predict the weight of a sand shark whose length is 75 inches.
Equation
Weight expected
b) Ifa sand shark weighs 200 pounds, what would you expect its length to be?

19

step-by-step explanation:

answer: idk

step-by-step explanation:

111

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.